Find the refractive index of the glass which a symmetrical convergent lens of its focal lengths is is equal to the radius of curvature of its surface. (A57)


Using formula: Lens Maker’s Formula:


f = focal length


R1 = radius of curvature of the lens surface closer to the source of light


R2 = radius of curvature of the lens surface farther to the source of light


n = Refractive index


Given: The lens is symmetrical. Therefore R1 = R2


According to sign convention: R1 = R & R2 = -R


focal length (f) = Radius of curvature(R)








2n-2 = 1


2n = 3


n = 3/2 = 1.5


n = Refractive index = 1.5


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