Construct trapezium PQRS with the following measurements. Find also its area.

is parallel to PQ = 6.8 cm, QR = 7.2 cm, PR = 8.4 cm and RS = 8 cm.

Given. PQRS is a trapezium.

PQ = 6.8 cm, RS = 8 cm , QR = 7.2 cm, PR = 8.4 cm

Formula used. Area of trapezium = × height × sum of parallel sides

Area of trapezium = × height × (PQ + SR)

Steps of Construction

Step 1 : Draw a line PQ of 6.8cm

Step 2 : Make an arc of 8.4cm from point P and 7.2cm from point Q

Step 3 : Mark the intersection point as R and join PR and QR

Step 4 : Draw a ray RS’ parallel to PQ from point R

Step 5 : Make arc of 8cm on ray RS’ from point R and name intersection point S

Step 6 : Join point S and P to form trapezium PQRS

Step 7 : Draw a perpendicular on PQ from point R and name the intersection point as E

Area of trapezium = × height × (PQ + SR)

= × RE × (PQ + SR)

= × 6.9cm × (6.8cm + 8cm)

= 51.06cm²

Conclusion. Hence; Trapezium PQRS is constructed and its area is

51.06cm²