Draw parallelogram ABCD with the following measurements and calculate its area.

AC = 10 cm, BD = 8 cm and ∠AOB = 100° where and intersect at ‘O’.

Given. ABCD is a parallelogram.

AC = 10 cm, BD = 8 cm

∠AOB = 100°

Formula used. Area of parallelogram = base × height

Steps of construction

Step 1 : Draw line segment AC of 10cm

Step 2 : Mark O as midpoint of AC

Step 3 : Draw line B’D’ through O which makes ∠AOB’ = 120°

Step 4 : Make Arcs of 4cm form O on both sides of B’D’

Step 5 : Join AB;BC;CD;DA

Step 6 : Draw a perpendicular on AB from point D and name the intersection point as E

Area of parallelogram = base × height

= AB × DE

= 5.7cm × 6.9cm

= 39.33cm²

Conclusion. Hence; parallelogram ABCD is constructed and its area

is 39.33cm²