Draw parallelogram ABCD with the following measurements and calculate its area.

AC = 8 cm, BD = 6 cm and ∠COD = 90° where and intersect at ‘O’.

Given. ABCD is a parallelogram.

AC = 8 cm, BD = 6 cm

∠COD = 90°

Formula used. Area of parallelogram = base × height

Steps of construction

Step 1 : Draw line segment AC of 8cm

Step 2 : Mark O as midpoint of AC

Step 3 : Draw line B’D’ through O which makes ∠COD’ = 120°

Step 4 : Make Arcs of 3cm form O on both sides of B’D’

Step 5 : Join AB;BC;CD;DA

Step 6 : Draw a perpendicular on AB from point D and name the intersection point as E

Area of parallelogram = base × height

= AB × DE

= 5cm × 4.8cm

= 24cm²

Conclusion. Hence; parallelogram ABCD is constructed and its area

is 24cm²