What is the hypotenuse of the right triangle with perpendicular sides √2 centimetres and √3 centimetres? How much larger than the hypotenuse is the sum of the perpendicular side?

We know that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
⇒ In ΔABC, BC2 = AB2 + AC2
⇒ BC2 = (√3)2 + (√2)2
⇒ BC2 = 3 + 2
⇒ BC2 = 5
∴ BC = √5 cm (Hypotenuse)
⇒ √5 ≈ 2.23 cm,
√2 ≈ 1.41 ,
and √3 ≈ 1.73
Sum of perpendicular sides = 1.41 + 1.73 = 3.14 cm
⇒ 3.14 – 2.23 = 0.91 cm
∴ The sum of perpendicular sides is 0.91 cm more than the hypotenuse.