In the picture below, two vertices of a parallelogram are joined to the midpoints of two sides.


Prove that these line divide the diagonal in the picture into three equal parts.


Given ,



Here AC and BD are diagonals and they bisect each other as we know.


Therefore we can say that AC is the median and passes through mid-poin of DB.


We know that


In any triangle, all the medians intersect at a single point and that point divides each median in the ratio 2:1 measured from vertex.


Therefore from triangle ABD,


We have


-------1


Similarly, from triangle BCD,


We have


; ----2


From 1 & 2


AG:GI:IC = AG:(GH + HI):IC


AG:GI:IC = 2:2:2 = 1:1:1


Hence the lines from vertices to mid-points of opposite side will divide the diagonal into three equal parts as shown above.


Hence proved.


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