Draw a triangle of circumradius 3 centimetres and two of the angles and
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We have to construct a triangle with ∠A = 32.5° ,
∠B = 37.5°
And, we know in a triangle, the sum of all angles is 180° .
Hence, the ∠C = 180 – 32.5 – 37.5
∴ ∠C = 110 degrees.
The circumradius = 3 cm.
Let’s say a = 3 cm, this is side BC.
1) First draw a line CD. At C and with a protractor make an angle of 110° , as shown,
2) With C as the centre and a radius of 3 cm cut the line CE. This point will be B.
3) At B, and with a protractor, make an angle of 75° with BC, as shown below:
Now, bisect the ∠CBR to get ∠CBN = 37/5°
4) The other angles can be measured with the help of the protactor.
This will be the required triangle.