Draw an isosceles right triangle of hypotenuse 4 centimetres.


1) Draw a line BC 4 cm.



2) At B, draw XBC = 45°



3) At C, draw YCB = 45°



BX and CY intersect each other at A. and ΔABC is required triangle,


Also,


In ΔABC


B = C = 45°


Therefore, AB = AC [i.e. ABC is isosceles]


And By angle sum property of triangle,


A + B + C = 180°


A + 45 + 45 = 180


A = 90°


Hence, ABC is isosceles.


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