The circuit diagram given below shows the combination of three resistors R₁, R₂ and R₃ :

Find:

(i) total resistance of the circuit.

(ii) total current flowing in the circuit.

(iii) the potential difference across R₁.

(i) As shown in the figure, the resistor R₂ and R₃ are connected in parallel. Their total resistance is given by

Here R2= 3 ohm and R3=6 ohm

So

R =2 ohm

The resistance R₁ is in series with the equivalent resistance which are parallel.

Total resistance of the circuit = 2+4ohms = 6ohms

(ii) Total current flowing through the circuit=Potential difference/total resistance

Here p.d =12V, and total resistance = 6 ohms

I = 12/6 = 2amps

(iii) The potential difference across R₁.

V = IR₁=2×4 =8V