In the circuit diagram given below five resistances of 10 Ω, 40 Ω, 30 Ω, 20 Ω and 60 Ω are connected as shown to a 12 V battery.

Calculate:

(a) total resistance in the circuit.

(b) total current flowing in the circuit.

(a) when three resistors are connected in parallel, the net resistance can be obtained as followed

The resistance of 30 ohm, 20 ohm and 60 ohm are connected in parallel. therefore, the net resistance R will be

----------------------- (1)

The resistance of 10 ohm and 60 ohm are connected in parallel. Therefore, the net resistance R will be

Now R₁ and R₂ are connected in series

So total resistance in the circuit is R = 10+8 =18 ohm

(b) Total current flowing in the circuit