In Fig. 2.15, points A, B, C, D and E are collinear such that

AB = BC = CD = DE. Then



(a) AD = AB + ____


(b) AD = AC + ____


(c) mid-point of AE is ____


(d) midpoint of CE is _____


(e) AE = _____ × AB.


(a) BD, (b) CD, (c) C, (d) C, (e) 5

Check for the part which is remaining.


L.H.S = R.H.S


21
1