In Fig. 2.15, points A, B, C, D and E are collinear such that
AB = BC = CD = DE. Then
(a) AD = AB + ____
(b) AD = AC + ____
(c) mid-point of AE is ____
(d) midpoint of CE is _____
(e) AE = _____ × AB.
(a) BD, (b) CD, (c) C, (d) C, (e) 5
Check for the part which is remaining.
L.H.S = R.H.S
21