In Fig. 6.15 all triangles are equilateraland AB = 8 units. Other triangles have been formed by taking the mid points of the sides. What is the perimeter of the figure?



Given other triangles are formed by taking midpoints


DF = FE = DE / 2


= 4 / 2


= 2 units


In Δ DIF


DI = DF = IF = 2 units


In Δ TKN and Δ RQU


TK = KN = TN = RQ = UQ = UR = 2 units


NC = RP = 2 units


IG = GF = 1 unit


In Δ HIG


HG = HI = GI = 1 unit


In Δ MLK and Δ XQS


ML = MK = LK = SQ = XS = QX = 1 unit


LN = XR = 1 unit


Perimeter = 4 + 2 + 1 + 1 + 1 + 2 + 4 + 4 + 2 +1 + 1 + 1 + 2 + 4 + 4 + 2 + 1 + 1 + 1 + 2 + 4


= 45 cm


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