In Fig. 6.15 all triangles are equilateraland AB = 8 units. Other triangles have been formed by taking the mid points of the sides. What is the perimeter of the figure?

Given other triangles are formed by taking midpoints

DF = FE = DE / 2

= 4 / 2

= 2 units

In Δ DIF

DI = DF = IF = 2 units

In Δ TKN and Δ RQU

TK = KN = TN = RQ = UQ = UR = 2 units

NC = RP = 2 units

IG = GF = 1 unit

In Δ HIG

HG = HI = GI = 1 unit

In Δ MLK and Δ XQS

ML = MK = LK = SQ = XS = QX = 1 unit

LN = XR = 1 unit

Perimeter = 4 + 2 + 1 + 1 + 1 + 2 + 4 + 4 + 2 +1 + 1 + 1 + 2 + 4 + 4 + 2 + 1 + 1 + 1 + 2 + 4

= 45 cm