Which of the following equations has x = 2 as a solution?


Given x = 2


Putting this value in each of the options, we check where LHS = RHS


A. x + 2 = 5


LHS = x +2 = 2 +2 =4


RHS = 5


LHS ≠RHS


B. x - 2 = 0


LHS = x - 2 = 2 - 2 = 0


RHS = 0


LHS = RHS


C. 2x + 1 = 0


LHS = 2x +1 = 2× 2 + 1=4 + 1 =5


RHS = 0


LHS ≠RHS


D. x + 3 = 6


LHS = x +3 = 2 +3 = 5


RHS = 6


LHS ≠RHS


Hence, x =2 is the solution of x-2 =0.

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