Write two equations for which 2 is the solution.

Let the two number be x and y, which has solution 2 in equation

1. For getting first equation, the number x is multiplied by 2, then the number is 2x

After that, 3 is subtracted from it which results into 1

Hence, 2x – 3 = 1

⇒ 2x = 3+1

⇒ 2x = 4

⇒x = 2

2. For getting second equation, the number y is multiplied by 3, then the number is 3y

After that, it will be added to 4 which results into 10

Hence, 3y + 4 = 10

⇒ 3y = 10-4

⇒ 3y = 6

⇒y = 2

Hence, required equation are 2x - 3 = 1 and 3y + 4 = 10