Write two equations for which 2 is the solution.


Let the two number be x and y, which has solution 2 in equation

1. For getting first equation, the number x is multiplied by 2, then the number is 2x


After that, 3 is subtracted from it which results into 1


Hence, 2x – 3 = 1


2x = 3+1


2x = 4



x = 2


2. For getting second equation, the number y is multiplied by 3, then the number is 3y


After that, it will be added to 4 which results into 10


Hence, 3y + 4 = 10


3y = 10-4


3y = 6



y = 2


Hence, required equation are 2x - 3 = 1 and 3y + 4 = 10


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