Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.

Question

Philoid · Accepted Answer

Least number which when divided by 3, 4 and 5 leaves remainder 0 in each case = LCM of 3, 4 and 5

3 = 3 × 1

4 = 2 × 2

5 = 5 × 1

LCM = 3 × 2 × 2 × 5 = 60

Hence, the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case = 60 + 2 = 62