Draw the graph of p(x) = x2 + 1 and find the real zeros of this polynomial.
Taking values as x = –3, –2, –1, 0, 1, 2, 3 in p(x), we obtain the following table:
Plotting these points on graph paper, we obtain the following figure:
The graph does not intersect the X -axis at any point.
∴ p(x) has no real zero.