Draw the graph of p(x) = x2 + 1 and find the real zeros of this polynomial.


Taking values as x = –3, –2, –1, 0, 1, 2, 3 in p(x), we obtain the following table:



Plotting these points on graph paper, we obtain the following figure:



The graph does not intersect the X -axis at any point.


p(x) has no real zero.


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