A gulab - jamun contain 40% sugar syrup in it. Find how much syrup would be there in 50 gulab - jamuns, each shaped like a cylinder with two hemispherical ends with total length 5 cm and diameter 2.8 cm.
Given.
40% of sugar syrup in 1 gulab - jamun
Having length is 5 cm
And diameter is 2.8 cm
Formula used/Theory.
Volume of cylinder = πr2h
Volume of hemisphere = 
πr3
If gulab - jamun shape like cylinder between 2 hemisphere
Volume of gulab - jamun = volume of cylinder
+ 2 × Volume of hemisphere
Diameter of hemisphere = 2.8 cm
Radius of hemisphere = 
= 1.4 cm
Height of cylinder = length of gulab - jamun–2 × radius
= 5 cm–2 × 1.4
= 5 cm – 2.8 cm
= 2.2 cm
Volume of gulab - jamun = volume of cylinder
+ 2 × Volume of hemisphere
= πr2h + 2 × 
πr3
= πr2[h + 
r]
= 
× 1.4 × 1.4 × [2.2 + 
× 1.4]
= 22 × 0.2 × 1.4 × [2.2 + 1.86]
= 22 × 0.2 × 1.4 × [4.06]
= 25.0096 cm3
Volume of sugar syrup = 
× 25.0096 cm3
Volume of sugar syrup = 10.0038 cm3
Volume of sugar syrup in 50 gulab - jamun = 50 × 10.0038 cm3
= 500.192 cm3
1 cm3 = 
litres
500.192 cm3 = 
litres
= 0.500192 litres
= 0.5 litres (approx.)