In figure PQ and RS are parallel. Then prove that ΔPOQ ~ ΔSOR.

Given,

PQ||RS

In ΔPOQ & ΔSOR,

⇒ ∠PQO = ∠ORS |Alternate angles

⇒ ∠QPO = ∠OSR |Alternate angles

⇒ ∠POQ = ∠ROS |Vertically opposite angles

Thus, ΔPOQ~ΔSOR by AAA Similarity Rule