Let us factorise the following algebraic expressions:

x2 – y2 – 6ax + 2ay + 8a2


Given,x2 – y2 – 2(3ax) + 2ay + 9a2 – a2


x2 – 2(3a)(x) + (3a)2 – (a2 – 2ay + y2)


(x – 3a)2 – (a – y)2


(x – 3a – a + y)(x – 3a + a – y)


[Since, from the identity III we know that, (x2 – y2) = (x – y)(x + y)]


(x – 4a + y)(x – 2a – y)


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