In parallelogram ABCD, AB = 4 cm., BC = 6 cm. and ∠ABC = 30°, find the area of field in the shape of parallelogram ABCD.

Question

In parallelogram ABCD, AB = 4 cm., BC = 6 cm. and ∠ ABC = 30°, find the area of field in the shape of parallelogram ABCD.

Philoid · Accepted Answer

Consider a parallelogram ABCD, such that AB = 4 cm, BC = 6 cm and ∠ABC = 30°, Draw AE ⊥ BC

We know, area of parallelogram = Base × Height

⇒ area(ABCD) = AE × BC

In ΔAEB

We know,

⇒ AE = 2 cm

Hence, area of ABCD = 2 × 6 = 12 cm²