A bus is moving with a speed 72 km/h can be stopped by brakes after at least 10 m. What will be the minimum stopping distance, if the same bus is moving at a speed of 144 km/h?

We have to first find the retardation.
Using the third equation of motion: v² – u² = 2as
where: s = distance covered = 10 m
v = final velocity = 0 m/s (brakes are applied so that bus
comes to rest)
u = initial velocity = 72 km/h = 20 m/s
a = acceleration = ? m/s²
v² – u² = 2as

0 – 20² = 2 × a × 10

-400 = 20 × a

= a

a = -20 m/s²

Now, u = initial velocity = 144 km/h = 40 m/s
s = distance covered = ?? m
v = final velocity = 0 m/s ( brakes are applied so that bus comes to rest)
a = acceleration = -20 m/s²

Using the third equation of motion: v² – u² = 2as

0 – 40² = 2 × -20 × s

-1600 = -40 × s

= s

s = 40 m