ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see Fig. 7.31). Show that these altitudes are equal.


It is given in the question that:


BE and CF are altitudes


AC = AB


To show: BE = CF


Proof: In


A = A (Common)


AEB = AFC (Right angles)


AB = AC (Given)


Therefore,


By AAS congruence axiom,



Thus,


BE = CF (By corresponding parts of congruent triangles)

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