Show that the angles of an equilateral triangle are 60° each.


Let us consider,

ABC be an equilateral triangle



BC = AC = AB (Length of all sides is same)


A = B = C (Sides opposite to the equal angles are equal)


Also,


A + B + C = 180o


3A = 180o


A = 60o


Therefore,


A = B = C = 60o


Thus,


The angles of an equilateral triangle are 60o each


8
1