BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.


It is given in the question that:

BE and CF are two equal altitudes



In


BEC = CFB = 90o (Altitudes)


BC = CB (Common)


BE = CF (Common)


Therefore,


By RHS axiom,



Now,


C = B (By c.p.c.t)


Thus,


AB = AC as sides opposite to the equal angles are equal


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