In Fig. 7.49, B < A and C < D. Show that AD < BC


It is given in the question that:

B < A and,


C < D


Now,


AO < BO (i) (Side opposite to the smaller angle is smaller)


OD < OC (ii) (Side opposite to the smaller angle is smaller)


Adding (i) and (ii), we get


AO + OD < BO + OC


AD < BC


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