Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
Let l is a line segment and B is a point lying to it. We draw a line AB perpendicular to l. Let C be any other point on l
To prove: AB < AC
Proof: In ,
∠B = 90o
Now,
∠A + ∠B + ∠C = 180o
∠A + ∠C = 90o
Therefore,
∠C must be acute angle or ∠C < ∠B
AB < AC (Sides opposite to the larger angle is larger)