In Fig. 9.24, ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD).


Consider ΔACD.

Line-segment CD is bisected by AB at O.Therefore, AO is the median of ΔACD


Area (ΔACO) = Area (ΔADO) (i)


Considering ΔBCD, BO is the median


Area (ΔBCO) = Area (ΔBDO) (ii)


Adding equations (i) and (ii), we get


Area (ΔACO) + Area (ΔBCO) = Area (ΔADO) + Area (ΔBDO)


Area (ΔABC) = Area (ΔABD)


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