What will be the angle of deviation through a prism and 60°, when angles of incidence and emergence are 45° each?
Given: Angle of prism, A = 60o
Angle of incidence, i = 45o
Angle of emergence e = 45o
To find: Angle of deviation = D
We know
A + D = i + e
So, D = i + e – A
D = 45o + 45o – 60o
= 30o
Hence angle of deviation is 30o