A soft drink bottle is dropped by a water from the top of a hotel whose height is 100 m. It takes T second to reach the ground. Where will it be at T/2 second?

Question

Philoid · Accepted Answer

Given:

Height of Tower = 100 m

Time taken to reach ground = T seconds

Acceleration = a = g = 9.8 ms^-2

Initial Speed = u = 0

Final Speed = v

Now, we know that,

At t = T and s = 100 m …..1

Let t = and s = x

Then, …..2

So, dividing equation 1 by 2, we get,

x = 25 m

So, 25 m from the top at t = seconds or (100 – 25) m, that is 75 m from the bottom at seconds.

Hence, option B is correct.