Construct a triangle ABC in which BC = 7cm, ∠B = 75° and AB + AC = 13 cm.
Steps of construction:
Step 1: Draw a line segment BC of 7cm.
Step 2: At point B, construct an angle XBY such that it is equal to 750 (Take the help of a contractor)
Step 3: A line segment BD = 13cm is cut on BX which is equal to (AB + AC).
Step 4: DC is joined and ∠DCY = ∠BDC is made.
Thus, ΔABC is the required triangle