Construct a triangle PQR in which QR = 6cm, ∠Q = 60° and PR – PQ = 2cm
Steps of construction:
Step 1: Draw a ray QX and cut off a line segment QR = 6cm from it.
Step 2: Construct a ray QY making an angle of 600 with QR and extend YQ to form a line YQY’
Step 3: Cut off a line segment QS = 2cm from QY’. And join RS.
Step 4: Draw a perpendicular bisector of RS intersecting QY at a point.
Step 5: PR is joined.
Thus, is the required triangle