The taxi fare in a city is as follows: For the first kilo-meter the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.
Total fare of the taxi = y
Total distance covered = x
Fair for the subsequent distance after 1st kilometer = Rs 5
Fair for 1st kilometer = Rs 8
As per the question,
y = 8 + 5 (x – 1)
y = 8 + 5x – 5
y = 5x + 3
x | 0 | -3/5 |
y | 3 | 0 |