A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.
Let ABCD be the given trapezium whose
parallel sides are:
AB = 25m and CD = 10m
And,
Non-parallel sides are AD = 13m and BC = 14m
Now,
CM perpendicular to AB and CE ‖ AD
In
BC = 14m, CE = AD = 13m and
BE = AB – AE
= 25- 10
= 15m
Semi perimeter of =
=
= 21cm
Now,
Using Heron’s formula,
Area of =
=
=
= 84m2
1/2 *15 *CM = 84
CM = m2
Area of parallelogram AECD = Base *Altitude
= AE *CM
= = 112m2
Area of trapezium ABCD = Area of AECD + Area of triangle BCE
= (112 + 84) m2
= 196m2