Find p(0), p(1) and p(2) for each of the following polynomials:

(i)

(ii)

(iii)

(iv)

(i) p(y) = y² – y + 1

p (0) = (0)² – (0) + 1 = 1

p (1) = (1)² – (1) + 1 = 1

p (2) = (2)² – (2) + 1 = 3

(ii) p(t) = 2 + t + 2t² – t³

p (0) = 2 + 0 + 2 (0)² – (0)³ = 2

p (1) = 2 + (1) + 2 (1)² – (1)³

= 2 + 1 + 2 – 1 = 4

p (2) = 2 + 2 + 2 (2)² – (2)³

= 2 + 2 + 8 – 8 = 4

(iii) p(x) = x³

p (0) = (0)³ = 0

p (1) = (1)³ = 1

p (2) = (2)³ = 8

(iv) p(x) = (x – 1) (x + 1)

p (0) = (0 – 1) (0 + 1) = (-1) (1) = -1

p (1) = (1 – 1) (1 + 1) = 0 (2) = 0

p (2) = (2 – 1) (2 + 1) = 1 (3) = 3