Find the zero of the polynomial in each of the following cases:

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)are real numbers.

(i) p (x) = x + 5

p (x) = 0

x + 5 = 0

x = -5

Therefore, x = -5 is a zero of the polynomial p(x) = x + 5

(ii) p (x) = x – 5

p (x) = 0

x – 5 = 0

x = 5

Therefore, x = 5 is a zero of the polynomial p(x) = x - 5

(iii) p (x) = 2x + 5

P (x) = 0

2x + 5 = 0

2x = -5

x =

Therefore, x = is a zero of the polynomial p(x) = 2x + 5

(iv) p (x) = 3x – 2

p (x) = 0

3x – 2 = 0

x =

Therefore, x = is a zero of the polynomial p(x) = 3x - 2

(v) p (x) = 3x

p (x) = 0

3x = 0

x = 0

Therefore, x = 0 is a zero of the polynomial p(x) = 3x

(vi) p (x) = ax

p (x) = 0

ax = 0

x = 0

Therefore, x = 0 is a zero of the polynomial p(x) = ax

(vii) p (x) = cx + d

p (x) = 0

cx + d = 0

x =

Therefore, x = is a zero of polynomial p (x) = cx + d