Find the remainder when is divided by

(i)


(ii)


(iii)


(iv)


(v)


(i) By long division method, we have


Therefore, the remainder is 0


(ii) By long division method, we have



Therefore, the remainder is


(iii)



Therefore, the remainder is 1


(iv)



Therefore, the remainder is [1 - 3π + 3π2 – π3]


(v)



Therefore, the remainder is


1
1