Find the value of k, if 
is a factor of p(x) in each of the following cases:
(i) 
(ii) 
(iii) 
(iv) 
(i) If x – 1 is a factor of polynomial p (x) = x2 + x + k, then
p (1) = 0
(1)2 + 1+ k = 0
2 + k = 0
k = -2
Therefore, value of k is -2
(ii) If x – 1 is a factor of polynomial p (x) = 2x2 + kx + 
, then
p (1) = 0
2(1)2 + k (1) + 
= 0
2 + k + 
= 0
k = -2 - 
= - (2 + 
)
Therefore, value of k is – (2 + 
)
(iii) If x – 1 is a factor of given polynomial p(x) = kx2 - 
x + 1, then
p (1) = 0
k (1)2 - 
(1) + 1 = 0
k - 
+ 1 = 0
k = 
- 1
Therefore, value of k is √2 – 1
(iv) If x – 1 is a factor of the given polynomial p(x) = kx2 – 3x + k, then
p (1) = 0
k(1)2 + 3(1) + k = 0
k – 3 + k = 0
2k – 3 = 0
k = 
Therefore, value of k is 
4