Find the length of the diagonal of a rectangle whose sides are 15 cm and 8 cm.


We have


Here, we are given with


CD = 15 cm


BD = 8 cm


We need to find BC.


So, by Pythagoras theorem that says


(Hypotenuse)2 = (Perpendicular)2 + (Base)2


BC2 = 82 + 152


BC2 = 64 + 225


BC2= 289


BC = √289


BC = 17


Thus, the length of diagonal is 17 cm.


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