The diameter of a sphere is decreased by 25%. By what per cent does it’s curved surface area decrease?
Let the diameter be d
Radius (r1) = ![]()
New radius (r2) =
(1 -
)
=
d
CSA (S1) = 4
r12
= 4π (
)2
= πd2
CSA (S2) = 4πr22
= 4π (
)2
=
d2
Decrease in surface area = S1 – S2
= πd2 -
d2
=
πd2
Now,
Percentage decrease =
* 100
=
* 100
= ![]()
= 43.75 %