Solve the following equations:

Given Differential equation is:
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⇒
……(1)
Homogeneous equation: A equation is said to be homogeneous if f(zx,zy) = znf(x,y) (where n is the order of the homogeneous equation).
Let us assume ![]()
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⇒ f(zx,zy) = z0f(x,y)
So, given differential equation is a homogeneous differential equation.
We need a substitution to solve this type of linear equation and the substitution is y = vx.
Let us substitute this in (1)
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We know that ![]()
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Bringing like variables on same side we get,
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We know that:
and
Also,
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Integrating on both sides, we get,
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(∵ log C is an arbitrary constant)
⇒ 
(∵ alogx = logxa)
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(∵ loga + logb = logab)
Since y = vx,
we get,
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⇒ 
⇒ 
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Applying exponential on both sides we get,
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∴ The solution of the Differential equation is
