Solve the following differential equations :
(i) If a differential equation is ,
then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx
Given:-
This is a linear differential equation, comparing it with
Q = log x
I.F = e∫Pdx
= elog|x|
= x, x>0
The solution of the equation is given by
y(I.F) = ∫Q.(I.F)dx + c
⇒ yx = ∫logx.x.dx + c