Find the values of y for which the distance between the points P(2, – 3) and Q (10, y) is10 units
It is given that the distance between (2, - 3) and (10, y) is 10
Therefore,
[(2 - 10)2 + (-3- y)2]1/2 = 10
[(-8)2 + (3+ y)2]1/2 = 10
64 + (y + 3)2 = 100
(y + 3)2 = 36
y + 3 = 
y + 3 = 6 or y + 3 = -6
Therefore, y = 3 or -9
9