Find the coordinates of the tip of the position vector which is equivalent to where the coordinates of A and B are (-1, 3) and (-2, 1) respectively.

Given A = (–1, 3) and B = (–2, 1)

We know position vector of a point (x, y) is given by, where and are unit vectors in X and Y directions.

Let position vectors of points A and B be and respectively.

We also have.

Recall the vector is given by

Now, it is given that there exists a point say (x, y) whose position vector is same as.

We know position vector of a point (x, y) is given by.

By comparing both the sides, we get x = –1 and y = –2

Thus, (–1, –2) is the tip of position vector that is same as .