Show that the direction cosines of a vector equally inclined to the axes OX, OY and OZ are


Let a vector be equally inclined to axes OX, OY, and OZ at angle

Then, the direction cosines of the vector are l = cosα, m = cosα and n = cos α


And, we know that –


l2 + m2 + n2 = 1


cos2α + cos2α + cos2α = 1


3 cos2α = 1



Hence, the direction cosines of the vector which are equally inclined to the axes are


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