Find the area of the parallelogram whose diagonals are :
and
Given two diagonals of a parallelogram are and
Let and
Recall the area of the parallelogram whose diagonals are given by the two vectors and
is
where
Here, we have (a1, a2, a3) = (4, –1, –3) and (b1, b2, b3) = (–2, 1, –2)
Recall the magnitude of the vector is
Now, we find.
Thus, the area of the parallelogram is 7.5 square units.