The two adjacent sides of a parallelogram are
and
Find the unit vector parallel to one of its diagonals. Also, find its area.
Let ABCD be a parallelogram with sides AB and AC given.
We have
and![]()

We need to find unit vector parallel to diagonal
.
From the triangle law of vector addition, we have
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Let the unit vector in the direction of
be
.
We know unit vector in the direction of a vector
is given by
.

Recall the magnitude of the vector
is
![]()
Now, we find
.
![]()
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So, we have![]()
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Thus, the required unit vector that is parallel to diaonal
is
.
Now, we have to find the area of parallelogram ABCD.
Recall the area of the parallelogram whose adjacent sides are given by the two vectors
and
is
where

Here, we have (a1, a2, a3) = (2, –4, 5) and (b1, b2, b3) = (1, –2, –3)

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Recall the magnitude of the vector
is
![]()
Now, we find
.
![]()
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Thus, area of the parallelogram is
square units.