Find the vector equation for the line which passes through the point (1, 2, 3) and parallel to the vector
Reduce the corresponding equation in Cartesian from.
here the vector for point A(1, 2, 3) is
and the vector parallel to which the line is required is ![]()
vector equation of a line is
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here
& ![]()
so the vector equation of the line is
![]()
Here x = 1 +
, y = 2–2
, z = 3 + 3![]()
![]()
Hence the cartesian equation of the above line is
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