Find the direction cosines of the line Also, reduce it to vector form.

the equation of the line is

But to make it cartesian equation the coefficient of x, y, z must be one so the above equation becomes as

Now the direction ratios of this line is ‹–2, 6, –3›

Concept of the question

Direction cosines of line

Are given as

Here

Hence direction cosines of the above line are

cartesian equation of the line is

Let this be equal to

Hence ….(1)

….(2)

Hence comparing 1&2