Find the points on the line at a distance of 5 units from the point P(1, 3, 3).

let Q be the point on the given line

It is of the form (3–2, 2–1, 2 + 3)

By letting

distance of point P from PQ =

So the points on the line are ((3(0)–2), (2(0)–1), (2(0) + 3)) and (3(2)–2, 2(2)–1, 2(2) + 3)

i.e. (–2, –1, 3) and (4, 3, 7)