Find the distance of the point (2, 4, –1) from the line 
Given: - Point P(2, 4, – 1) and equation of line ![]()
Let, Q be a point through which line passes
Thus from given equation of line coordinates of Q is
Q( – 5, – 3,6)
As we know line equation with direction ratio of given line is parallel to given line.
Hence Line is parallel to![]()
Now,
⇒ ![]()
⇒ ![]()
Now let's find cross product of this two vectors
⇒ 
⇒ ![]()
The magnitude of this cross product
⇒ ![]()
⇒ ![]()
And Magnitude of ![]()
⇒ ![]()
⇒ ![]()
Thus distance of point from line is
⇒ 
⇒ 
⇒
units